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M is a 2x2 singular matrix with tr M = 26. What is the value of the smaller eigenvalue of M? It is not necessary to know Mexactly.

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Answer:

0

Explanation:

Let the two eigen values are a and b

As we have given that trace of the matrix is 26

So a+b=26 (property of eigen value )

As the matrix is a singular matrix so the determinant of the matrix will be zero

So ab =0 ( property of the eigen values)

For ab =0 any one of the eigen value must be 0

If one eigen value will be zero then other will be 26

So the smaller eigen value will be zero

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