Answer:
The length side of the pre-image is 16 units
Explanation:
we know that
The length side of the image is equal to the length side of the pre-image multiplied by the scale factor
or
The length side of the pre-image is equal to the length side of the image divided by the scale factor
in this problem we have that
The scale factor is 1/2
The length side of the image is 8 units
therefore
8/(1/2)=16 units
The length side of the pre-image is 16 units