Answer:
B.197 gpm and 12.4 L/s
Step-by-step explanation:
Given that
Load Q = 404.5 KW
Water inlet temperature= 6.1 °C
Water outlet temperature= 13.9°C
We know that specific heat for water
Now from energy balance
by putting the values
(1 Kg/s = 15.85 gal/min)
We can say that
We know that
12.38=1000 x volume flow rate
So
volume flow rate = 12.38 L/s
So the option B is correct.