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In a double-slit experiment, the third-order maximum for light of wavelength 520 nm is located 17 mm from the central bright spot on a screen 1.6 m from the slits. Light of wavelength 630 nm is then projected through the same slits. How far from the central bright spot will the second-order maximum of this light be located?

User Sai Mukesh
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1 Answer

2 votes

Answer:

The distance from the central bright spot is 13.73 mm.

Step-by-step explanation:

Given that,

Wavelength = 520 nm

Width d= 17 mm

Distance L= 1.6 m

Order = 3

We need to calculate the distance from the central bright spot

Using formula of distance


y=(m\lambda L)/(d)

Put the value into the formula


y=(3*520*10^(-9)*1.6)/(17*10^(-3))


y=0.0001468=146.8*10^(-6)\ m

Now, the wavelength is changed to 630 nm

We need to calculate the distance from the central bright spot with the second order of this light


y=(2*630*10^(-9)*1.6)/(146.8*10^(-6))


y=0.0137=13.73*10^(-3)\ m


y=13.73\ mm

Hence, The distance from the central bright spot is 13.73 mm.

User Rufus L
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