Question

Four dice are rolled. What is the probability of getting exactly three ""4’s"" and one ""2"" in any order?

Answer 1

Step-by-step explanation:

Given that four dice are rolled.

Probability for getting 4 in any dice =
`(1)/(6)` and

Probability for getting 2 in any dice =
`(1)/(6)`

Since each die is independent of the other the probability would be

=
`4C1((1)/(6))^3( (1)/(6))\\=0.003086`

Step-by-step explanation:

2 can occur either I or II or III or Iv hence we multiply by 4C1 and multiply 1/6, 4 times.