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Show explicitly that ▽ . B-0 near a long straight wire carrying a current I. HINT: you may use Cartesian coordinates, but another choice might make it easier

User EthanP
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1 Answer

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Answer:


\bigtriangledown.B=0 is proved.

Step-by-step explanation:

The magnetic field in the long current carrying wire is,


B=(\mu_(0)I )/(2\pi r ) \phi

Here, I is the current, B is the magnetic field.

Now, by using cylindrical coordinates for the divergence of B.


\bigtriangledown.B=(1)/(s) (d)/(d\phi) B

Put the value of B in above equation.


\bigtriangledown.B=(1)/(s) (d)/(d\phi)((\mu_(0)I )/(2\pi r ) \phi)\\\bigtriangledown.B=0

Hence, it is prove that for a long current I carrying wire magnetic field divergence that is
\bigtriangledown.B=0.

User Yam Tal
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