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The function f(x) = -(x-3)2 + 9 can be used to represent the area of a rectangle with a perimeter of 12 units, as a function of

the length of the rectangle, x. What is the maximum area of the rectangle?

2 Answers

2 votes

Answer:

C. 9

Explanation:

EDG2020

User Kevin Hogg
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1 vote

Answer:

Maximum area = 9 sq units

Explanation:


f(x)=-(x-3)^2+9

which represents the area . As it is a quadratic equation it represents the parabola . And the vertex of the parabola will maximum area of for some value of x

let f(x) = y


y=-(x-3)^2+9


(x-3)^2=-(y-9)

Comparing it with the standard equation of parabola


y=(x-h)^2+k

we get h=3 and y=9

where (h,k) is the vertex (3,9)

Hence the maximum area of the rectangle will be 9

User Tom Crockett
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