Answer:
Maximum area = 9 sq units
Explanation:
![f(x)=-(x-3)^2+9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tprvcl5hhtorm6dgajnplzljcxczzhnj8i.png)
which represents the area . As it is a quadratic equation it represents the parabola . And the vertex of the parabola will maximum area of for some value of x
let f(x) = y
![y=-(x-3)^2+9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mr5grs3q0fghqaoliod5t718e40gktwf4b.png)
![(x-3)^2=-(y-9)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3gcf0tnlzlsie8z0idweuofds2ct9j88h7.png)
Comparing it with the standard equation of parabola
![y=(x-h)^2+k](https://img.qammunity.org/2020/formulas/mathematics/high-school/plf39mbuj3m07p7q4grnlgeoy0063edjvk.png)
we get h=3 and y=9
where (h,k) is the vertex (3,9)
Hence the maximum area of the rectangle will be 9