232k views
1 vote
1. 4g of Hydrogen react with 30 g of Nitrogen, how many gram of Ammonia is formed? 3 H2 + N2 + 2NH3

User Reem Aziz
by
8.0k points

1 Answer

3 votes

Answer: The mass of ammonia formed is 22.61 grams

Step-by-step explanation:

To calculate the number of moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} .....(1)

  • For Hydrogen gas:

Given mass of hydrogen gas = 4 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:


\text{Moles of hydrogen gas}=(4g)/(2g/mol)=2mol

  • For nitrogen gas:

Given mass of nitrogen gas = 30 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:


\text{Moles of nitrogen gas}=(30g)/(28g/mol)=1.07mol

The chemical equation for the formation of ammonia follows:


3H_2+N_2\rightarrow 2NH_3

By Stoichiometry of the reaction:

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas.

So, 2 moles of hydrogen gas will react with =
(1)/(3)* 2=0.66mol of nitrogen gas.

As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of hydrogen gas produces 2 moles of ammonia

So, 2 moles of hydrogen gas will produce =
(2)/(3)* 2=1.33moles of ammonia

  • Now, calculating the mass of ammonia from equation 1, we get:

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 1.33 moles

Putting values in equation 1, we get:


1.33mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=22.61g

Hence, the mass of ammonia formed is 22.61 grams

User Mike Hogan
by
7.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.