Question

1. 4g of Hydrogen react with 30 g of Nitrogen, how many gram of Ammonia is formed? 3 H2 + N2 + 2NH3

Answer 1

Answer: The mass of ammonia formed is 22.61 grams

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` .....(1)

• For Hydrogen gas:

Given mass of hydrogen gas = 4 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

`\text{Moles of hydrogen gas}=(4g)/(2g/mol)=2mol`

• For nitrogen gas:

Given mass of nitrogen gas = 30 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in equation 1, we get:

`\text{Moles of nitrogen gas}=(30g)/(28g/mol)=1.07mol`

The chemical equation for the formation of ammonia follows:

`3H_2+N_2\rightarrow 2NH_3`

By Stoichiometry of the reaction:

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas.

So, 2 moles of hydrogen gas will react with =
`(1)/(3)* 2=0.66mol` of nitrogen gas.

As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of hydrogen gas produces 2 moles of ammonia

So, 2 moles of hydrogen gas will produce =
`(2)/(3)* 2=1.33moles` of ammonia

• Now, calculating the mass of ammonia from equation 1, we get:

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 1.33 moles

Putting values in equation 1, we get:

`1.33mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=22.61g`

Hence, the mass of ammonia formed is 22.61 grams