Question

A garden hose discharges water at the rate of 15 m/s. If the nozzle is held at ground level and directed θ = 30° from the ground, determine the maximum height reached by the water and the horizontal distance from the nozzle to where the water strikes the ground.

Answer 1

Answer:2.87m ,19.88 m

Step-by-step explanation:

Given

water velocity (V)=15 m/s

nozzle angle
`=30 ^(\circ)`

it is similar to projectile motion

and maximum height is given by

`H=(v^2sin^2\theta )/(2g)`

`H=(15^2sin^2(30))/(2* 9.81)`

`H=(225* (1)/(4))/(2* 9.81)`

H=2.87 m

Horizontal Distance
`=(v^2sin2\theta )/(g)`

`H=(15^2sin(60))/(9.81)`

H=19.88 m