Answer:
![n=40](https://img.qammunity.org/2020/formulas/mathematics/high-school/j76e4onwze7c8aph0scscgs66zfomz438l.png)
Step-by-step explanation:
We want to know the value of
when
![P=480](https://img.qammunity.org/2020/formulas/business/college/a16z211e07v22voc158k9ihul9153w2bt3.png)
![P=3n^2-90n-720\\480=3n^2-90n-720\\3n^2-90n-720-480=0\\3n^2-90n-1200=0\\3(n^2-30n-400)=0\\n^2-30n-400=0](https://img.qammunity.org/2020/formulas/business/college/fv7ey05tb63saszi9ytia05lkqjwivpazv.png)
From here, we can find the factors of the quadratic equation, we need two numbers that multiplied give -400 and added -30. Since they are factors of 400, we can choose -20x20 or -40x10. When adding -20 and 20 the result is zero, but the sum of -40 and 10 is -30. Then:
![n^2-30n-400=0\\(n-40)(n+10)=0\\](https://img.qammunity.org/2020/formulas/business/college/jc7j7adslpwh5cscjrpbmuz37mgroq5yq8.png)
The solutions of the quadratic equation are
and
:
![n_1=40\\n_2=-10](https://img.qammunity.org/2020/formulas/business/college/ixg6z949guu9aab1s4nswqja5g87y5emig.png)
Since
is a positive integer:
![n=40](https://img.qammunity.org/2020/formulas/mathematics/high-school/j76e4onwze7c8aph0scscgs66zfomz438l.png)