Question

What is E of a hydrogen atom in the 3p state?

What is L (as a multiple of ℏ) of a hydrogen atom in the 3p state?

Answer 1

E=-1.51 eV.

`L=\hbar√(2)`

Step-by-step explanation:

The nth level energy of a hydrogen atom is defined by the formula,

`E_(n)=-(13.6)/(n^(2) )`

Given in the question, the hydrogen atom is in the 3p state.

Then energy of n=3 state is,

`E_(n)=-(13.6)/((3)^(2) )\\E_(n)=-1.51eV`

Therefore, energy of the hydrogen atom in the 3p state is -1.51 eV.

Now, the value of L can be calculated as,

`L=\hbar√(l(l+1))`

For 3p state, l=1

`L=\hbar√(1(1+1))\\L=\hbar√(2)`

Therefore, the value of L of a hydrogen atom in 3p state is
`L=\hbar√(2)`.