The length of a rectangular mailing label is 2 centimeters less than twice the width. The perimeter is 50 centimeters. Find the dimensions of the label.

Question

asked Jun 20, 2020 128k views

2 Answers

PapaSmurf · Answer 1 · 2020-06-22T21:05:34+0000

Answer:

$Length=16\ cm\\\\Width=9\ cm$

Explanation:

We know that the lenght (
) of the rectangular mailing label is 2 centimeters less than twice the width (
). This is:

l=2w-2

The formula for calculate the perimeter of a rectangle is:

P=2l+2w

Then, we must substitute the perimeter and
l=2w-2 into the formula
P=2l+2w and solve for "w":

$50=2(2w-2)+2w\\\\50=4w-4+2w\\\\54=6w\\\\w=9$

Now substitute the value of "w" into
l=2w-2 to find the lenght. Then:

l=2(9)-2=16

Therefore, the dimensions are:

$Length=16\ cm\\\\Width=9\ cm$

CigarDoug · Answer 2 · 2020-06-25T12:50:21+0000

Answer:

The width is 9 cm and the length is 16 cm

Explanation:

Let the width be x centimeters.

If the length of a rectangular mailing label is 2 centimeters less than twice the width, then the length is 2x-2 centimeters.

The perimeter is the sum of all sides, so

$x+(2x-2)+x+(2x-2)=50\\ \\x+2x-2+x+2x-2=50\\ \\6x-4=50\\ \\6x=54\\ \\x=9\\ \\2x-2=2\cdot 9-2=18-2=16$

The width is 9 cm and the length is 16 cm