Question

A(n) 30 kg boy rides a roller coaster. The acceleration of gravity is 9.8 m/s 2 . With what force does he press against the seat when the car moving at 7.3 m/s goes over a crest whose radius of curvature is 15 m? Answer in units of N.

Answer 1

Force, F = 187.42 N

Step-by-step explanation:

It is given that,

Mass of boy, m = 30 kg

Acceleration due to gravity,
`a=9.8\ m/s^2`

Radius of curvature of the roller coaster, r = 15 m

Speed of the car, v = 7.3 m/s

The force acting on the boy are force of gravity and the centripetal force. The net force acting on him is as follows :

`F=mg-(mv^2)/(r)`

`F=m(g-(v^2)/(r))`

`F=30* (9.8-((7.3)^2)/(15))`

F = 187.42 N

So, he press against the seat with a force is 187.42 N. Hence, this is the required solution.