Question

Dion has a pizza with a diameter of 10 1/3 in . Is the square box shown big enough to fit the pizza inside? The box is 10.38 in wide and the pizza is 10 1/3 inches wide?

please HELP ME

Answer 1

The pizza fit inside the box

Explanation:

we have that

The diameter of the pizza is

`D=10(1)/(3)\ in`

The wide of the square box is

`b=10.38\ in`

we know that

For the pizza to fit inside the box, it must be fulfilled that

`D \leq b`

Convert 10.38 in to fraction number

`10.38((100)/(100))=(1,038)/(100)=(519)/(50)`

Convert
`10(1)/(3)\ in` to an improper fraction

`10(1)/(3)=(10*3+1)/(3)=(31)/(3)`

Multiply the diameter of the pizza by 50 both numerator and denominator

`(31*50)/(50*3)=(1,550)/(150)\ in`

Multiply the wide of the box by 3 both numerator and denominator

`(519*3)/(50*3)=(1,557)/(150)\ in`

compare

`(1,550)/(150)\ in < (1,557)/(150)\ in`

therefore

The pizza fit inside the box