Question

A mass of mercury occupies 0.750 L. What volume would an equal mass of ethanol occupy? The density of mercury is 13.546 g/mL, and the density of ethanol is 0.789 g/mL.

Answer 1

To find the volume that an equal mass of ethanol would occupy, we can use the concept of density as a conversion factor. By setting up a proportion and solving for the volume of ethanol, we find that it would occupy a volume of approximately 0.0437 L.

Step-by-step explanation:

To find the volume that an equal mass of ethanol would occupy, we can use the concept of density as a conversion factor. The density of mercury is 13.546 g/mL, and the density of ethanol is 0.789 g/mL. Since the mass of the mercury is equal to the mass of ethanol, we can set up a proportion:

(Volume of mercury) / (Density of mercury) = (Volume of ethanol) / (Density of ethanol)

Plugging in the given values, we have:

(0.750 L) / (13.546 g/mL) = (Volume of ethanol) / (0.789 g/mL)

Cross-multiplying and solving for the volume of ethanol, we get:

Volume of ethanol = (0.750 L * 0.789 g/mL) / (13.546 g/mL) = 0.0437 L

Therefore, an equal mass of ethanol would occupy a volume of approximately 0.0437 L.

Answer 2

Ve=12876.43mL : Ethanol volume

Step-by-step explanation:

We apply the formula to calculate the density:

ρ=
`(m)/(V)` Formula (1)

Where:

ρ:Density in g/mL

m: mass in g (grams)

V= Volume in ml (milliliters)

We know the following data:

1L= 1000mL

Vm=Volume of mercury:VHg=0.750 L*1000mL/L=750mL

ρ-m=Density of mercury =13.546 g/mL

ρ-e: density of ethanol is 0.789 g/mL

`m_(m) =m_(e)`

Development of the problem:

In formula 1 We replace the known data for the mercury :

ρ-m=
`(m_(m) )/(V_(m) )`

`13.546 (g)/(mL) =(m_(m) )/(750mL)`

`m_(m)=13.546 (g)/(mL)*750mL`

`m_(m) =10159.5 g`

We know that
`m_(e) =m_(m) =10159.5 g`, then, We replace the known data for the ethanol In formula 1:

ρ-e=
`(m_(e) )/(V_(e) )`

`0.789 (g)/(mL) =(10159.5g)/(V_(e) )`

`Ve=(10159.5 g)/(0.789 (g)/(mL))`

`Ve=12876.43mL`