Question

The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed

of objects on the planet's surface? Round your answer to the nearest whole number
m/s
Done

Answer 1

241

Explanation:

answer is 241

Answer 2

`v_(tan)=276.18 \pi (km)/(hr)`

Explanation:

Givens:

• 
  `r=3,397 \ km`
• 
  `T=24.6 \ hours`

Where
`r` is the radius and
`T` is the period, that is, the time used to complete one rotation.

The tangential speed is defined as:

`v_(tan)=(r \Delta \theta)/(\Delta t)`

Where
`\theta` is the angular movement or the angle, and
`t` the time used during the movement.

In this case, the angular movement is one rotation which is
`2\pi`. Now, we replace all given values:

`v_(tan)=((3,397 \ km) (2\pi))/(24.6 \ hours)\\v_(tan)=276.18 \pi (km)/(hr)`

Therefore, the tangential speed is
`v_(tan)=276.18 \pi (km)/(hr)`