Answer:
65%
Explanation:
First, we find the area of the square. The side has length 24 in.
As = s^2 = (24 in.)^2 = 576 in.^2
Now we find the area of the largest circle. The radius is 8 in.
Ac = (pi)r^2 = 3.14159(8 in.)^2 = 3.14159(64 in.^2) = 201.1 in.^2
The area of the region inside the square but outside the largest circle is
As - Ac = 576 in.^2 - 201.1 in.^2 = 374.938 in.^2
The probability of landing inside the square but outside the largest circle is the area of the region inside the square but outside the largest circle divided by the area of the square.
p(outside largest circle) = (374.938 in.^2)/(576 in.^) = 0.6509 = 65%