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A bird launches into flight from a point on the ground. The bird can fly 8 feet per second horizontally and 6 feet per second vertically. After 10 seconds, how far has the bird flown relative to its initial spot on the ground?

User Rido
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1 Answer

5 votes

Answer:

Explanation:

Given that a bird launches into flight from a point on the ground. The bird can fly 8 feet per second horizontally and 6 feet per second vertically.

Net speed would be using Pythagorean theorem =
√(8^2+6^2) =10

After 10 seconds, it would be 10(10) = 100 feet from its initial spot on the ground.

User TheMrbikus
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