Answer:
Explanation:
Given are five numbers x, 7, 2, 16, and 11
Average = sum/5=
![(x+36)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8zobof0rkwjhs6d3ouee66h5xafcvjv0o4.png)
Median =
![(x+36)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8zobof0rkwjhs6d3ouee66h5xafcvjv0o4.png)
The average of the remaining four numbers =
![(36)/(4) =9](https://img.qammunity.org/2020/formulas/mathematics/high-school/74d1qi01nic38utvdsq5mjk66wg4po7pug.png)
If x=9 then average =9 only and also median
will be middle entry of ascending order
2,7,9,11,16
Middle entry = Median = 9
Hence x=9
(1) 7 < x < 11