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What should be added to x^3+4x^2+5, so that it is completely divisible by x^2+5? Here ^=power or exponent guys please please solve this sum it is urgent 5 points on it please

1 Answer

6 votes

Answer: 5x + 15

Explanation:

Divide (x² + 5) into (x³ + 4x² + 5) to see what is needed to make a remainder of zero.

Let k represent the unknown number.

x + 4

x² + 5 ) x³ + 4x² + 0x + 5+k

- (x³ + 5x)

4x² - 5x + 5+k

- (4x² + 20)

In order to have a remainder of zero, 4x² -5x + 5 + k must equal 4x² + 20

Solve for k:

4x² -5x + 5 + k = 4x² + 20

-5x + 5 + k = 20 subtracted 4x² from both sides

5 + k = 5x + 20 added 5x to both sides

k = 5x + 15 subtracted 5 from both sides

User Darren Smith
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