202k views
2 votes
What should be added to x^3+4x^2+5, so that it is completely divisible by x^2+5? Here ^=power or exponent guys please please solve this sum it is urgent 5 points on it please

1 Answer

6 votes

Answer: 5x + 15

Explanation:

Divide (x² + 5) into (x³ + 4x² + 5) to see what is needed to make a remainder of zero.

Let k represent the unknown number.

x + 4

x² + 5 ) x³ + 4x² + 0x + 5+k

- (x³ + 5x)

4x² - 5x + 5+k

- (4x² + 20)

In order to have a remainder of zero, 4x² -5x + 5 + k must equal 4x² + 20

Solve for k:

4x² -5x + 5 + k = 4x² + 20

-5x + 5 + k = 20 subtracted 4x² from both sides

5 + k = 5x + 20 added 5x to both sides

k = 5x + 15 subtracted 5 from both sides

User Darren Smith
by
9.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories