Question

In anticipation of winter snowstorms, Ole fill his 2.50 gal gas can at the local gas station. a. If the temp. is 65.3 F on the day he fills the gas can, what volume of gas will Ole have when the temp. drops to 10.5 F? b. If gas the gas costs $1.97/gas, how much money does Ole lose?

Answer 1

Ole was at loss of $0.5142.

Step-by-step explanation:

Volume of the gas at 65.3°F =
`V_1=2.50 gal`

Volume of gas at 10.5°F =
`V_2=?`

Fahrenheit to Kelvin conversion:

`((T)F- 32)* (5)/(9) + 273.15 = (T)K`

`T_1=65.3^oF=291.65 K`

`T_2=10.5^oF=261.2056 K`

Using Charles law: Volume of gas is directly related to temperature of the gas under constant pressure.

`(V_1)/(T_1)=(V_2)/(T_2)`

`V_2=(2.50 gal* 261.2056 K)/(291.65 K)=2.2390 gal`

Cost of 1 gal of gas = $1.97

Cost of 2.50 gal of gas = 2.50 × $1.97 =$4.925

Cost of 2.2390 gal of gas = 2.2390 × $1.97 =$4.4108

Loss of money = $4.925 - $4.4108 = $0.5142