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The heating element of an iron operates at 110 V with a current of 9A. (a) What is the resistance of the iron?

(b) What is the power dissipated by the iron?

1 Answer

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Answer:

(A) 12.222 ohm (B) 990 W

Step-by-step explanation:

We have given the voltage of the heating element V = 110 V

The current in the heating element i = 9 A

(a) According to ohm's law V =iR

So
110=9* R


R=(110)/(9)=12.222ohm

(b) The power dissipated in the resistor is given by
P=i^2R=9^2* 12.222=990W

So the power dissipated = 990 W

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