Question

Given the function f(x) = −3x2 + 4x + 6, find f(2) and f(3). Choose the statement that is true concerning these two values.

Answer 1

For this case we have the following function:

`f (x) = - 3x ^ 2 + 4x + 6`

We must evaluate the function when
`x = 2`and
`x = 3`

For
`x = 2`:

`f (2) = - 3 (2) ^ 2 + 4 (2) +6\\f (2) = - 3 * 4 + 8 + 6\\f (2) = - 12 + 8 + 6`

Different signs are subtracted and the major sign is placed.

Equal signs are added and the same sign is placed.

`f (2) = - 4 + 6\\f (2) = 2`

For
`x = 3`:

`f (3) = - 3 (3) ^ 2 + 4 (3) +6\\f (3) = - 3 * 9 + 12 + 6\\f (3) = - 27 + 12 + 6`

Different signs are subtracted and the major sign is placed.

Equal signs are added and the same sign is placed.

`f (3) = - 15 + 6\\f (3) = - 9`

Answer:

`f (2) = 2\\f (3) = - 9`

Answer 2

f(x)= −3x^2 + 4x + 6;

f(2) = 2;

f(3) = -9

Explanation:

You have to substitute the values for the given functions. Remember to use PEDMAS for the order of operations: parentheses, exponents, division, multiplication, addition, and then substitution.

We'll insert 2 for the value of x for the first one.

f(2)= (-3)*2^2 + 4*2 + 6

f(2) = (-3)*4+ 4*2+6

f(2) = -12 + 8 + 6

f(2) = -12 + 14

f(2) = 2

We'll insert 3 for the value of x for the second one.

f(3) = (-3)*3^2+4*3+6

f(3) = (-3)*9+4*3+6

f(3) = -27 + 12 + 6

f(3) = -9