Question

Two 0.75 Amp loads are connected in parallel with a 2500 Milliamperehour Ni-Cd battery. Approximately how long can the battery provide power to the load?

Answer 1

Step-by-step explanation:

It is given that two loads have 0.75 Ampere current each. And, they contain 2500 milli ampere per hour Ni-Cd battery.

As both the loads are connected in parallel. Hence, total current will be calculated as follows.

I =
`I_(1) + I_(2)`

= 0.75 A + 0.75 A

= 1.5 A

=
`1.5 A * (1000 mA)/(1 A)`

= 1500 mA

Relation between time and capacity of battery is as follows.

Capacity = Current × time (in hour)

therefore, time =
`(Capacity)/(Current)`

=
`(2500 mA. h)/(1500 A)`

= 1.667 hr

Thus, we can conclude that the battery provide power to the load up to 1.667 hours.