Question

A coin with diameter 2.00 cm is placed horizontally in water at a depth of 20.0 cm. The refractive index of water is 1.33 Find the apparent position and size of the image of the coin when viewed at normal incidence from a point above the surface.

Answer 1

apparent position = 26.6 cm

and size is same of coin because we observe it directly above of the coin

Step-by-step explanation:

given data

diameter = 2 cm

depth = 20 cm

refractive index of water = 1.33

to find out

apparent position and size

solution

we know refractive index of air is 1

so apparent position of coin formula is

apparent position =
`(refractive index of water)/(refractive index of air) (depth)` ..........................1

put here value in equation 1

apparent position =
`(1.33)/(1) (20)`

apparent position = 26.6 cm

and size is same of coin because we observe it directly above of the coin