Answer:
The atmospheric pressure is found to be
![104.378kPa](https://img.qammunity.org/2020/formulas/engineering/college/zrs04x10yhvjs64lbjks3vke2ho4nq6w28.png)
Step-by-step explanation:
We know that pressure exerted by a standing column of fluid is calculated using the equation
![P=\rho _(fluid)* gh](https://img.qammunity.org/2020/formulas/engineering/college/37wp4f7w86lulkuxajtpkk4nxpsve4dqj0.png)
In our case the pressure of the standing column of mercury is equal to the atmospheric pressure.
According to the given data we have
![\rho _(fluid)=14000kg/m^(3)](https://img.qammunity.org/2020/formulas/engineering/college/zyu0pm4c3op2mnml2jxwjxywelhrk4k0ep.png)
![g=9.81m/s^(2)](https://img.qammunity.org/2020/formulas/engineering/college/lf8yd3atp3cuper3m7uq479i2vvcizjuif.png)
![h=760mm=0.76m](https://img.qammunity.org/2020/formulas/engineering/college/jwdt7x210unmazg4p56kxqxr7nsa7bfjm6.png)
Using the values in the equation above we calculate atmospheric pressure to be
![P_(atm)=14000* 9.81* 0.760\\\\=104.378kPa](https://img.qammunity.org/2020/formulas/engineering/college/wpl3ilb8nxevx5vyjr2sazxfu7kz1ym3cd.png)