Question

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.

What is the smallest possible perimeter of the triangle, rounded to the nearest tenth?

Answer 1

72.4 inch

Explanation:

Length of the longest side = 30 inch

Let the length of two congruent side is x.

As the triangle is acute and the two sides are congruent, so it means it is an isosceles right angled triangle.

So, length of longest side is hypotenuse.

By use of Pythagoras theorem

`hypotenuse^(2)=base^(2)+height^(2)`

`30^(2)= x^(2)+x^(2)`

`900^(2)=2x^(2)`

x = 21.2 inch

Perimeter = sum of all the sides

P = 30 + 21.2 + 21.2 = 72.4 inch

Answer 2

Good evening ,

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Answer:

≈72,4

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Explanation:

Look at the photo below for the details.

:)