Answer: The required number is 91.
Step-by-step explanation: Given that a number has a tens digit that is 8 more than the ones digit. Zero is not one of the digits.
We are to find the number.
Let x and y represents the digit in ten's place and one's place respectively.
So, the number is
![n=10x+y.](https://img.qammunity.org/2020/formulas/mathematics/high-school/7s5tfqnxenr7hvcqc0xyoxy6yl1gsz52xe.png)
According to the given information, we have
![x=8+y.](https://img.qammunity.org/2020/formulas/mathematics/high-school/ynrlb8dlix1ld8hou0mxofoik4ajk7su1k.png)
Therefore,w e get
![n=10x+y=10(8+y)+y=80+11y.](https://img.qammunity.org/2020/formulas/mathematics/high-school/57ws23qldm5sr1i7ihgb1rhmtkr6ukny7v.png)
Since the number is of two digits and x, y are not zero, so the required value of y is 1.
That is, given number is
![n=80+11*1=91.](https://img.qammunity.org/2020/formulas/mathematics/high-school/5jnttb4xf532ni84oys35cwzxob5djfrig.png)
Thus, the required number is 91.