Question

A capacitor is connected to an ac power supply. The maximum current is 4.0 A and the reactance of the capacitor is Xc = 8.0 Ω. What is the average power dissipated by the capacitor? Select one: a. 32 W b.0 W c. 128 W d. 64 W

Answer 1

option (b)

Step-by-step explanation:

Io = 4 A

Xc = 8 ohm

The formula for the average power dissipated is given by

P = Vrms x Irms x cos Ф

Where, Ф be the phase difference between Vrms and Irms .

As we know that in case of capacitor, the current leads the voltage by 90 degree, it means the value of Ф is 90 degree.

Thus, Average power = Vrms x Irms x Cos 90

Average power = 0 Watt