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Calculate the slope of the line that passes through the points (-4,-7) and (1,-7)​

User Lynx
by
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2 Answers

2 votes


\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-7}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-7}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{(-4)}}}\implies \cfrac{-7+7}{1+4}\implies \cfrac{0}{5}\implies 0

User Ortex
by
8.3k points
5 votes

Answer:

slope = 0

Explanation:

m= slope

m= (y2-y1)/(x2-x1)

we have:

(-4,-7) and (1,-7)​

m= (-7-(-7)) / (1-(-4))

m= 0/ 5

m=0

User Justinsg
by
7.3k points

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