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Find the compound interest earned by the deposit. $16,000 @3% annually for 13 years

User Prokky
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\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+(r)/(n)\right)^(nt) \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$16000\\ r=rate\to 3\%\to (3)/(100)\dotfill &0.03\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &13 \end{cases} \\\\\\ A=16000\left(1+(0.03)/(1)\right)^(1\cdot 13)\implies A=16000(1.03)^(13)\implies A\approx 23496.5394

User Kennedy Oliveira
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