Step-by-step explanation:
It is given that,
Velocity of arrow, v = 32 m/s
Height above ground, h = 295 m
Let t is the time taken by arrow in air. It is given by :

a = g
Initially, u = 0


t = 7.75 seconds
Let it land at a distance of d. It is given by :


d = 248 meters
Hence, this is the required solution.