Step-by-step explanation:
It is given that,
Velocity of arrow, v = 32 m/s
Height above ground, h = 295 m
Let t is the time taken by arrow in air. It is given by :
![h=ut+(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/college/ng1x6ggu07lojvmbh5by32t7rvb09ncc7y.png)
a = g
Initially, u = 0
![t=\sqrt{(2h)/(g)}](https://img.qammunity.org/2020/formulas/physics/college/qgyqtxas1btff6fcr7w1eioh78b6j04acn.png)
![t=\sqrt{(2* 295)/(9.8)}](https://img.qammunity.org/2020/formulas/physics/college/2rp934dlnqhxjf1y5jxyek2uve6r29raqn.png)
t = 7.75 seconds
Let it land at a distance of d. It is given by :
![d=v* t](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5saovervhbexg664fxszt3uynixwo2lgpl.png)
![d=32* 7.75](https://img.qammunity.org/2020/formulas/physics/college/oa6k4h62cj2eytxhdzwubvwwft3bsmma0o.png)
d = 248 meters
Hence, this is the required solution.