Question

A 460 nm monochromatic light is split into two beams. The two beams arrive at a point on a screen with a path difference of 920nm. Calculate the phase difference.

Answer 1

phase difference
`\Delta \Phi = 12.566`

Step-by-step explanation:

Phase difference is expressed as
`\Delta \Phi`

`\Delta \Phi =\frac {2\pi}{\lambda} \Delta X`

Where,

`\Delta \Phi`= phase difference

`\lambda` wavelength = 460nm

`\Delta X` path difference = 920 nm

`\Delta \Phi =\frac {2\pi}{460} *920 = 4\pi`

therefore

phase difference
`\Delta \Phi = 12.566`