Question

Two 4.3546 cm x 4.3546 cm square aluminum electrodes, spaced 0.6408 mm apart are connected to a 73.68 V battery. What is the capacitance in pico Farads?

Answer 1

Capacitance, C = 26.1 picofarad

Step-by-step explanation:

It is given that,

Side of square, x = 4.3546 cm = 0.043546 m

Distance between electrodes, d = 0.6408 mm = 0.0006408 m

Voltage, V = 73.68 V

Capacitance of parallel plates is given by :

`C=(\epsilon_oA)/(d)`

`C=(8.85* 10^(-12)* (0.043546)^2)/(0.0006408)`

`C=2.61* 10^(-11)\ F`

or

C = 26.1 picofarad

So, the capacitance of the capacitor is 26.1 picofarad. Hence, this is the required solution.