Question

The distance between two parallel wires carrying currents of 10 A and 20 A is 10 cm. Determine the magnitude and direction of the magnetic force acting per unit length of the wires if the currents are carried in the same direction.

Answer 1

Step-by-step explanation:

It is given that,

Current in wire 1, I₁ = 10 A

Current in wire 2, I₂ = 20 A

Distance between wires, d = 10 cm = 0.1 m

Force per unit length is given by :

`(F)/(l)=(\mu_oI_1I_2)/(2\pi r)`

`(F)/(l)=(4\pi * 10^(-7)* 10* 20)/(2\pi * 0.1)`

`(F)/(l)=0.0004\ N/m`

`(F)/(l)=4* 10^(-4)\ N/m`

So, the magnetic force acting per unit length of the wires
`4* 10^(-4)\ N/m`. Since, the current is in same direction. So, the force is attractive in nature.