Answer:
Bore = 7 cm
stroke = 6.36 cm
compression ratio = 10.007
Step-by-step explanation:
Given data:
Cubic capacity of the engine, V = 245 cc
Clearance volume, v = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
V =
![(\pi)/(4)D^2L](https://img.qammunity.org/2020/formulas/engineering/college/ycag1qo5rf5aejil95otfiksddwoinra3m.png)
or
V =
![(\pi)/(4)(D^3)/(1.1)](https://img.qammunity.org/2020/formulas/engineering/college/pzeimm381rvnllhanofu3kfj7hfd9w13cs.png)
on substituting the values, we have
245 =
![(\pi)/(4)(D^3)/(1.1)](https://img.qammunity.org/2020/formulas/engineering/college/pzeimm381rvnllhanofu3kfj7hfd9w13cs.png)
or
D = 7.00 cm
Now,
we have
D/L = 1.1
thus,
L = D/1.1
L = 7/1.1
or
L= 6.36 cm
Now,
the compression ratio is given as:
![\textup{compression ratio}=(V+v)/(v)](https://img.qammunity.org/2020/formulas/engineering/college/v7m5fiqzn50izhvyr209vqohbbe1du3jsu.png)
on substituting the values, we get
![\textup{compression ratio}=(245+27.2)/(27.2)](https://img.qammunity.org/2020/formulas/engineering/college/qeb98hywtirezrrd1algxaxwgcodebe2ze.png)
or
Compression ratio = 10.007