We have a solenoid made of stainless steel with 50 turns/m. The diameter of the wire is 2mm and when stretched it is 10m. What is the value of the magnetic field inside, in the …

Question

asked Oct 14, 2020 203k views

1 Answer

Miguel Ruivo · Answer 1 · 2020-10-21T01:51:03+0000

Answer:

The value of the magnetic field inside in the center is
$0.89759*10^(-3)\ T$ .

Step-by-step explanation:

Given that,

Number of turns per length = 50

Diameter = 2 mm

Stretched = 10 m

Voltage = 5 V

We need to calculate the resistance

Using formula of

$R=(\rho l)/(A)$

$R=(4\rho l)/(\pi d^2)$

Put the value into the formula

$R=(4*1.1*10^(-7)*10)/(\pi*(2*10^(-3))^2)$

$R=0.35\ \Omega$

We need to calculate the magnetic field

Using formula of magnetic field

$B = \mu_(0)nI$

$B=\mu_(0)n*(V)/(R)$

$B=4\pi*10^(-7)*50*(5)/(0.35)$

$B=0.89759*10^(-3)\ T$

Hence, The value of the magnetic field inside in the center is
$0.89759*10^(-3)\ T$ .