Question

We have a solenoid made of stainless steel with 50 turns/m. The diameter of the wire is 2mm and when stretched it is 10m. What is the value of the magnetic field inside, in the center, when we apply a 5v DC voltage at its ends?

Answer 1

The value of the magnetic field inside in the center is
`0.89759*10^(-3)\ T`.

Step-by-step explanation:

Given that,

Number of turns per length = 50

Diameter = 2 mm

Stretched = 10 m

Voltage = 5 V

We need to calculate the resistance

Using formula of

`R=(\rho l)/(A)`

`R=(4\rho l)/(\pi d^2)`

Put the value into the formula

`R=(4*1.1*10^(-7)*10)/(\pi*(2*10^(-3))^2)`

`R=0.35\ \Omega`

We need to calculate the magnetic field

Using formula of magnetic field

`B = \mu_(0)nI`

`B=\mu_(0)n*(V)/(R)`

`B=4\pi*10^(-7)*50*(5)/(0.35)`

`B=0.89759*10^(-3)\ T`

Hence, The value of the magnetic field inside in the center is
`0.89759*10^(-3)\ T`.