Question

A 2135 cm3 sample of dry air has a pressure of 98.4 kpa at 127 degrees Celsius. What is the volume of the sample if the Temperature is increased to 206degrees c when the pressure is kept constant

Answer 1

the equation is p1 x v1 divided by T1 = p1 x v2 = T2 but since the pressure is kept constant you do not even need it so the equation would now be v1 divided by t1 = v2 divided by t2

2135 cm3 divided by 127 degrees celcius = x divided by 206

answer: 3460 cm3

Answer 2

The volume of the sample if the temperature is increased to 206°C when the pressure is kept constant is 3,463.07 cm³.

Step-by-step explanation:

Charles's Law consists in the relationship between the volume and temperature of a certain amount of ideal gas, where constant pressure is maintained. The relationship is produced by means of a constant of proportionality. Then, at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

In summary, Charles's law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

`(V)/(T)=k`

It is now possible to assume that you have a certain volume of V1 gas that is at a temperature V1 at the beginning of the experiment. If you vary the volume of gas to a new V2 value, then the temperature will change to T2, and it will be met:

`(V1)/(T1) =(V2)/(T2)`

In this case:

• V1=2135 cm³
• T1=127 °C
• V2=?
• T2=206 °C

Then:

`(2135 cm^(3) )/(127 C) =(V2)/(206 C) \\`

Solving you get:

`V2=(2135 cm^(3) )/(127C) *206 C`

V2=3,463.07 cm³

The volume of the sample if the temperature is increased to 206°C when the pressure is kept constant is 3,463.07 cm³.