Question

An object is located 21.0 cm to the left of a diverging lens having a focal length f = -40.0 cm. (a) Determine the location of the image. (b) Determine the magnification of the image.

(c) Construct a ray diagram for this arrangement.

Answer 1

(a). The image distance is 13.77 cm to the left side of a lens.

(b). The magnification of the image is -0.655

Step-by-step explanation:

Given that,

Object distance u= 21.0 cm

Focal length f= -40.0 cm

(a). We need to calculate the image distance

Using formula of lens

`(1)/(f)=(1)/(v)-(1)/(u)`

Put the value into the formula

`(1)/(-40)=(1)/(v)-(1)/(-21)`

`(1)/(v)=(1)/(-40)+(1)/(-21)`

`(1)/(v)=-(61)/(840)`

`v=-13.77\ cm`

(b). We need to calculate the magnification of the image

Using formula of magnification

`m=-(v)/(u)`

Put the value into the formula

`m=-(13.77)/(21.0)`

`m=-0.655`

Hence, (a). The image distance is 13.77 cm to the left side of a lens.

(b). The magnification of the image is -0.655