Answer:
Q=3198.744 W/m
Step-by-step explanation:
Given that
Air temperature=20 C
Velocity V= 35 m/s
Temperature of surface= 60 C
Length of plate= 75 cm
Now first find the properties of air at mean temperature of 20 and 60,it means that properties of air at temperature 40 C
![\rho=1.12 (Kg)/(m^3)](https://img.qammunity.org/2020/formulas/engineering/college/gyd0s83dhwc4lzt9zgsga9ecxmc50qnqy8.png)
![\\u =1.69* 10^(-5)(m^2)/(s)](https://img.qammunity.org/2020/formulas/engineering/college/1uwyy51jb81sgjvwunkyv4if4djvdo9koj.png)
![K=0.027(W)/(m-K)](https://img.qammunity.org/2020/formulas/engineering/college/db4vm8q7heiub5tj98nbn0sd623kwjl1i7.png)
Pr=0.71
Lets find the Reynolds number
![Re=(vL)/(\\u )](https://img.qammunity.org/2020/formulas/engineering/college/qhnyi377mvrkmirp4g8wvi870emyyrflye.png)
![Re=(35*0.75)/(1.69* 10^(-5))](https://img.qammunity.org/2020/formulas/engineering/college/zn18l4pan20mgbdemx8k5un694yz4ofi66.png)
![Re=15.53*10^5](https://img.qammunity.org/2020/formulas/engineering/college/57mutvlslqgzalxt4ip08sjlqoarja636v.png)
So this is turbulent flow
Nusselt equation of turbulent flow
![Nu=0.037Re^{(4)/(5)}Pr^{(1)/(3)}](https://img.qammunity.org/2020/formulas/engineering/college/di6lx07h7352t1id00ktajtuudekh071dq.png)
Now by putting the values
![Nu=0.037* (15.53*10^5)^{(4)/(5)}* 0.71^{(1)/(3)}](https://img.qammunity.org/2020/formulas/engineering/college/el7qp6x9pz6m48jcew60t5lux4wga7sv29.png)
Nu=2961.68
We know that
![NU=(hL)/(K_(air))](https://img.qammunity.org/2020/formulas/engineering/college/db3zshcl2y50ymwfio5pe8kknqatb127nv.png)
So
![2961.68=(h* 0.75)/(0.027)](https://img.qammunity.org/2020/formulas/engineering/college/8up6wcn2jrdva1tx8b67jmb5wamsg8xkvg.png)
![h=106.68(W)/(m^2-K)](https://img.qammunity.org/2020/formulas/engineering/college/xyo9ysw18jhp0oystsr9sqoqjnm5awl8mq.png)
So heat transfer
Q=hAΔT
Q=106.68 x 0.75 x 1 x (60-20)
Q=3198.744 W/m