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Find (f-g)(x) when f(x)=2x+6/3x and g(x)=(sqrt)x-8/3x

Find (f-g)(x) when f(x)=2x+6/3x and g(x)=(sqrt)x-8/3x-example-1
User ThiagoLeal
by
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2 Answers

4 votes

Answer:

( 2x - √x + 14 ) /3x

Explanation:

[ Refer to the attachment ]

Find (f-g)(x) when f(x)=2x+6/3x and g(x)=(sqrt)x-8/3x-example-1
User Boris Kirov
by
8.2k points
5 votes

Answer:

see below

Explanation:


(f-g)(x)=f(x)-g(x)=(2x+6)/(3x)-(√(x)-8)/(3x)\\\\=(2x+6-(√(x)-8))/(3x)=(2x-√(x)+14)/(3x)

The difference function is the difference of the functions. Since both have the same denominator, the numerator of the difference is the difference of numerators. When -8 is subtracted, it is the same as adding 8, so the numerator of the difference will have the constant 6+8 = 14. Only one choice matches.

Find (f-g)(x) when f(x)=2x+6/3x and g(x)=(sqrt)x-8/3x-example-1
User CaioT
by
8.6k points

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