Answer:
The length of rectangle is approximately 13.86 feet and width is 6.93 feet.
Explanation:
Let x represent width of the rectangle.
We have been given that the length is 2 times the width, then length would be
.
We have been given that the area of the rectangle is 96 square feet.
We know that area of rectangle is length times width, so we can represent this information in an equation as:
![2x\cdot x=96](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gc8nmoijtlr8ahe0owsnlbm47mqjgo1vi4.png)
![2x^2=96](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ui01moi08wjg5ukti1lri3ijeazii6hwh8.png)
![(2x^2)/(2)=(96)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ftgky8f3i3sztrjhgb6bfiow6muxx41p12.png)
![x^2=48](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9dcv983ma42n7j31xyxhc8l4ve2tnk096n.png)
Take square root of both sides:
![x=\pm √(48)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/13w44hxllcvfqf9j9mt0y5uov3m34k7hnx.png)
![x=\pm 6.92820](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hki5fvoi0zcq06xh8cyyev8nd9upad6wmq.png)
![x\approx \pm 6.93](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a5t77k4u0o79sw8v0wk2l7iseyaaosmzc2.png)
Since width cannot be negative, therefore, the width of the rectangle would be 6.93 feet.
The length is 2 times width, so length would be:
![2* 6.93\approx 13.86](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mstu8acmzrv68kldr4c6o378wnpndrmmpy.png)
Therefore, the length of rectangle is approximately 13.86 feet.