Answer:
$300.
Explanation:
Let x represent original cost of each hard drive.
We have been given that IBM states that it makes a 30% profit over its expenses for producing hard drives.
The cost of each hard drive after profit would be x plus 30% of x.
![\text{The cost of each hard drive after profit}=x+(30)/(100)x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ei4p0a99s79buawekp9h0csnd0wb0ysqu7.png)
![\text{The cost of each hard drive after profit}=x+0.30x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i3kot4o96qszzkxisurnbfqpay4mcb075l.png)
![\text{The cost of each hard drive after profit}=1.30x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1ije4cy2qnjdrv3aqq6opafvvw8ui5s4ak.png)
We have been given that IBM sells each hard drive for $390. We can represent this information in an equation as:
![1.30x=\$390](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aofokx1m4pchbbncvku10ajvckq0mb52r7.png)
![(1.30x)/(1.30)=(\$390)/(1.30)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/umill4lp0nxg2myyh3ixme7zggv3dirwfm.png)
![x=\$300](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2r46ereblaj3witpi17bmwh026zxwoxb8q.png)
Therefore, the original cost of each hard drive is $300.