Answer:
270 m
Step-by-step explanation:
When the driver hits the brakes, the kinetic energy of the car is converted by friction into heat. The kinetic energy K is given by:
(1)
![K=(1)/(2) mv^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/377oeoqwdvpxbz25ynss6agz30i8ff6np4.png)
The work W done by friction is:
(2)
![W = F_fd](https://img.qammunity.org/2020/formulas/physics/middle-school/y85lti218w1p3kcootj6tw8guyxd92xsc6.png)
where the force of friction is:
![F_f = \mu mg](https://img.qammunity.org/2020/formulas/physics/middle-school/8cerdfcxk4w0bnfjgs1kx9e0m0vye8swy2.png)
d: distance sliding
μ: friction coefficient
m: mass
g: gravitational constant
setting equation 1 and 2 equal:
(3)
![(1)/(2)mv^(2)=\mu mgd](https://img.qammunity.org/2020/formulas/physics/middle-school/zuer4do6x89u8udtsmcbujurnfaeyc7oes.png)
simplifying:
(4)
![d = (v^(2) )/(2\mu g)](https://img.qammunity.org/2020/formulas/physics/middle-school/uul08ewvrw7e2e6wf5tsx23laf0kcb4bex.png)
Use equation 4 to find the ratio between the two cases gives:
(5)
![(d_1)/(d_2) = (v_1^(2) )/(v_2^(2) )](https://img.qammunity.org/2020/formulas/physics/middle-school/p1i4qh90im5zv3wfhfgsr2lb00qh5xfmb3.png)
plugging in:
![(30)/(d_2)=(60^(2) )/(180^(2))](https://img.qammunity.org/2020/formulas/physics/middle-school/uqmgiixbgzn9gqsg87gi10gge1hx9ovg1n.png)
![d_2=270](https://img.qammunity.org/2020/formulas/physics/middle-school/9gqvaaw58cgibch993lzn8i44cwwnnb5qe.png)