For this case we have to by definition, if two lines are parallel then their slopes are equal.
We find the slope of the line AB:
![(x1, y1): (- 3,0)\\(x2, y2): (- 6,5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qikua1aay0e74q2you3p9gv8dr8zkmu0xq.png)
![m = \frac {y2-y1} {x2-x1} = \frac {5-0} {- 6 - (- 3)} = \frac {5} {- 6 + 3} = \frac {5} { -3} = - \frac {5} {3}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/el5cs63rfoakttwpb33ebyf3nhdvhw812c.png)
Thus, the parallel line is of the form:
![y = - \frac {5} {3} x + b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kxdz1z9gtrm2j9vknfpfd4pnkwo6l4g1o0.png)
If the line passes through the origin, then we have the point (0,0):
![0 = - \frac {5} {3} (0) + b\\b = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kj2w99f0as13c3db2mii1tznj0b2bqnsfi.png)
Then, the equation is:
![y = - \frac {5} {3} x\\3y = -5x\\3y + 5x = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4cufiikrv5ykmtqh1sfxylyru8xxk69m1y.png)
Answer:
OPTION C